(x+5)(x-2)=x2-16

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Solution for (x+5)(x-2)=x2-16 equation: 



(x+5)(x-2)=x2-16

We move all terms to the left:

(x+5)(x-2)-(x2-16)=0

We add all the numbers together, and all the variables

-(+x^2-16)+(x+5)(x-2)=0

We get rid of parentheses

-x^2+(x+5)(x-2)+16=0

We multiply parentheses ..

-x^2+(+x^2-2x+5x-10)+16=0

We add all the numbers together, and all the variables

-1x^2+(+x^2-2x+5x-10)+16=0

We get rid of parentheses

-1x^2+x^2-2x+5x-10+16=0

We add all the numbers together, and all the variables

3x+6=0

We move all terms containing x to the left, all other terms to the right

3x=-6

x=-6/3

x=-2

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