(x+5)(x-3)(x-3)(x+5)=48

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Solution for (x+5)(x-3)(x-3)(x+5)=48 equation: 



(x+5)(x-3)(x-3)(x+5)=48

We move all terms to the left:

(x+5)(x-3)(x-3)(x+5)-(48)=0

We multiply parentheses ..

(+x^2-3x+5x-15)(x-3)(x+5)-48=0

We multiply parentheses ..

(+x^2-3x+5x-15)(+x^2+5x-3x-15)-48=0

We move all terms containing x to the left, all other terms to the right

(+x^2-3x+5x-15)(+x^2+5x-3x-15)=48

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