(x+5)(x-3)=x(x-2)

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Solution for (x+5)(x-3)=x(x-2) equation: 



(x+5)(x-3)=x(x-2)

We move all terms to the left:

(x+5)(x-3)-(x(x-2))=0

We multiply parentheses ..

(+x^2-3x+5x-15)-(x(x-2))=0



We calculate terms in parentheses: -(x(x-2)), so:

x(x-2)

We multiply parentheses

x^2-2x

Back to the equation:

-(x^2-2x)



We get rid of parentheses

x^2-x^2-3x+5x+2x-15=0

We add all the numbers together, and all the variables

4x-15=0

We move all terms containing x to the left, all other terms to the right

4x=15

x=15/4

x=3+3/4

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