(x+5)(x-4)=x(+7x+20)

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Solution for (x+5)(x-4)=x(+7x+20) equation:



(x+5)(x-4)=x(+7x+20)
We move all terms to the left:
(x+5)(x-4)-(x(+7x+20))=0
We add all the numbers together, and all the variables
(x+5)(x-4)-(x(7x+20))=0
We multiply parentheses ..
(+x^2-4x+5x-20)-(x(7x+20))=0
We calculate terms in parentheses: -(x(7x+20)), so:
x(7x+20)
We multiply parentheses
7x^2+20x
Back to the equation:
-(7x^2+20x)
We get rid of parentheses
x^2-7x^2-4x+5x-20x-20=0
We add all the numbers together, and all the variables
-6x^2-19x-20=0
a = -6; b = -19; c = -20;
Δ = b2-4ac
Δ = -192-4·(-6)·(-20)
Δ = -119
Delta is less than zero, so there is no solution for the equation

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