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(x+5)(x-5)=816
We move all terms to the left:
(x+5)(x-5)-(816)=0
We use the square of the difference formula
x^2-25-816=0
We add all the numbers together, and all the variables
x^2-841=0
a = 1; b = 0; c = -841;
Δ = b2-4ac
Δ = 02-4·1·(-841)
Δ = 3364
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3364}=58$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-58}{2*1}=\frac{-58}{2} =-29 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+58}{2*1}=\frac{58}{2} =29 $
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