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(x+5)(x-5)=x(+5x)
We move all terms to the left:
(x+5)(x-5)-(x(+5x))=0
We use the square of the difference formula
x^2-(x(+5x))-25=0
We calculate terms in parentheses: -(x(+5x)), so:We add all the numbers together, and all the variables
x(+5x)
We multiply parentheses
5x^2
Back to the equation:
-(5x^2)
-4x^2-25=0
a = -4; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·(-4)·(-25)
Δ = -400
Delta is less than zero, so there is no solution for the equation
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