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(x+5)(x-5)=x(+6x)
We move all terms to the left:
(x+5)(x-5)-(x(+6x))=0
We use the square of the difference formula
x^2-(x(+6x))-25=0
We calculate terms in parentheses: -(x(+6x)), so:We add all the numbers together, and all the variables
x(+6x)
We multiply parentheses
6x^2
Back to the equation:
-(6x^2)
-5x^2-25=0
a = -5; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·(-5)·(-25)
Δ = -500
Delta is less than zero, so there is no solution for the equation
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