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(x+5)(x-6)=51
We move all terms to the left:
(x+5)(x-6)-(51)=0
We multiply parentheses ..
(+x^2-6x+5x-30)-51=0
We get rid of parentheses
x^2-6x+5x-30-51=0
We add all the numbers together, and all the variables
x^2-1x-81=0
a = 1; b = -1; c = -81;
Δ = b2-4ac
Δ = -12-4·1·(-81)
Δ = 325
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{325}=\sqrt{25*13}=\sqrt{25}*\sqrt{13}=5\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-5\sqrt{13}}{2*1}=\frac{1-5\sqrt{13}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+5\sqrt{13}}{2*1}=\frac{1+5\sqrt{13}}{2} $
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