(x+5)-2(3-4x)=5(x+3)-4

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Solution for (x+5)-2(3-4x)=5(x+3)-4 equation: 



(x+5)-2(3-4x)=5(x+3)-4

We move all terms to the left:

(x+5)-2(3-4x)-(5(x+3)-4)=0

We add all the numbers together, and all the variables

(x+5)-2(-4x+3)-(5(x+3)-4)=0

We multiply parentheses

(x+5)+8x-(5(x+3)-4)-6=0

We get rid of parentheses

x+8x-(5(x+3)-4)+5-6=0



We calculate terms in parentheses: -(5(x+3)-4), so:

5(x+3)-4

We multiply parentheses

5x+15-4

We add all the numbers together, and all the variables

5x+11

Back to the equation:

-(5x+11)



We add all the numbers together, and all the variables

9x-(5x+11)-1=0

We get rid of parentheses

9x-5x-11-1=0

We add all the numbers together, and all the variables

4x-12=0

We move all terms containing x to the left, all other terms to the right

4x=12

x=12/4

x=3

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