(x+5)-2;(4x-1)=0

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2x+y=8
x+3y=14

Solution for (x+5)-2;(4x-1)=0 system of equations: 


  • /| x-2+5 = 0| 4*x-1 = 0
  • We try to solve the equation: x-2+5 = 0
  • x+3 = 0 // - 3
  • x = -3
  • We insert the solution into one of the initial equations of our system of equations
  • We get a system of equations:
  • /| -3*4-1 = 0| x = -3
  • -12-1 = 0
  • -(1+12) = 0
  • -13 = 0
  • The system of equations does not have any solution

 

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