(x+5)-2x+(1-6x)=10(2-3x)

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Solution for (x+5)-2x+(1-6x)=10(2-3x) equation: 



(x+5)-2x+(1-6x)=10(2-3x)

We move all terms to the left:

(x+5)-2x+(1-6x)-(10(2-3x))=0

We add all the numbers together, and all the variables

(x+5)-2x+(-6x+1)-(10(-3x+2))=0

We add all the numbers together, and all the variables

-2x+(x+5)+(-6x+1)-(10(-3x+2))=0

We get rid of parentheses

-2x+x-6x-(10(-3x+2))+5+1=0



We calculate terms in parentheses: -(10(-3x+2)), so:

10(-3x+2)

We multiply parentheses

-30x+20

Back to the equation:

-(-30x+20)



We add all the numbers together, and all the variables

-7x-(-30x+20)+6=0

We get rid of parentheses

-7x+30x-20+6=0

We add all the numbers together, and all the variables

23x-14=0

We move all terms containing x to the left, all other terms to the right

23x=14

x=14/23

x=14/23

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