(x+5)/(2x-4)=7/3

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Solution for (x+5)/(2x-4)=7/3 equation: 



(x+5)/(2x-4)=7/3

We move all terms to the left:

(x+5)/(2x-4)-(7/3)=0



Domain of the equation: (2x-4)!=0

We move all terms containing x to the left, all other terms to the right

2x!=4

x!=4/2

x!=2

x∈R



We add all the numbers together, and all the variables

(x+5)/(2x-4)-(+7/3)=0

We get rid of parentheses

(x+5)/(2x-4)-7/3=0

We calculate fractions


(3x+15)/(6x-12)+(-14x+28)/(6x-12)=0

We multiply all the terms by the denominator


(3x+15)+(-14x+28)=0

We get rid of parentheses

3x-14x+15+28=0

We add all the numbers together, and all the variables

-11x+43=0

We move all terms containing x to the left, all other terms to the right

-11x=-43

x=-43/-11

x=3+10/11

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