(x+5)/(4x-10)=(30)/(75)

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Solution for (x+5)/(4x-10)=(30)/(75) equation: 



(x+5)/(4x-10)=(30)/(75)

We move all terms to the left:

(x+5)/(4x-10)-((30)/(75))=0



Domain of the equation: (4x-10)!=0

We move all terms containing x to the left, all other terms to the right

4x!=10

x!=10/4

x!=2+1/2

x∈R



We add all the numbers together, and all the variables

(x+5)/(4x-10)-(+30/75)=0

We get rid of parentheses

(x+5)/(4x-10)-30/75=0

We calculate fractions


(75x+375)/(300x-750)+(-120x+300)/(300x-750)=0

We multiply all the terms by the denominator


(75x+375)+(-120x+300)=0

We get rid of parentheses

75x-120x+375+300=0

We add all the numbers together, and all the variables

-45x+675=0

We move all terms containing x to the left, all other terms to the right

-45x=-675

x=-675/-45

x=+15

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