(x+5)/(4x-10)=(30)/(75)

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Solution for (x+5)/(4x-10)=(30)/(75) equation:



(x+5)/(4x-10)=(30)/(75)
We move all terms to the left:
(x+5)/(4x-10)-((30)/(75))=0
Domain of the equation: (4x-10)!=0
We move all terms containing x to the left, all other terms to the right
4x!=10
x!=10/4
x!=2+1/2
x∈R
We add all the numbers together, and all the variables
(x+5)/(4x-10)-(+30/75)=0
We get rid of parentheses
(x+5)/(4x-10)-30/75=0
We calculate fractions
(75x+375)/(300x-750)+(-120x+300)/(300x-750)=0
We multiply all the terms by the denominator
(75x+375)+(-120x+300)=0
We get rid of parentheses
75x-120x+375+300=0
We add all the numbers together, and all the variables
-45x+675=0
We move all terms containing x to the left, all other terms to the right
-45x=-675
x=-675/-45
x=+15

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