(x+5)/(x+4)=1/(x+4)

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Solution for (x+5)/(x+4)=1/(x+4) equation: 


D( x )

x+4 = 0

x+4 = 0

x+4 = 0

x+4 = 0 // - 4

x = -4

x in (-oo:-4) U (-4:+oo)

(x+5)/(x+4) = 1/(x+4) // - 1/(x+4)

(x+5)/(x+4)-(1/(x+4)) = 0

(x+5)/(x+4)-(x+4)^-1 = 0

(x+5)/(x+4)-1/(x+4) = 0

x-1+5 = 0

x+4 = 0

(x+4)/(x+4) = 0

(x+4)/(x+4) = 0 // * x+4

x+4 = 0

x+4 = 0 // - 4

x = -4

x in { -4} 

x belongs to the empty set

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