(x+5)/2+1/2=2x-(x-3)/8

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Solution for (x+5)/2+1/2=2x-(x-3)/8 equation:



(x+5)/2+1/2=2x-(x-3)/8
We move all terms to the left:
(x+5)/2+1/2-(2x-(x-3)/8)=0
We calculate fractions
(x+5)/()+(-(2x-(x-3)*2)/()=0
We calculate terms in parentheses: +(-(2x-(x-3)*2)/(), so:
-(2x-(x-3)*2)/(
We multiply all the terms by the denominator
-(2x-(x-3)*2)
We calculate terms in parentheses: -(2x-(x-3)*2), so:
2x-(x-3)*2
We multiply parentheses
2x-2x+6
We add all the numbers together, and all the variables
6
Back to the equation:
-(6)
Back to the equation:
+(-6)
We add all the numbers together, and all the variables
(x+5)/()-6=0
We multiply all the terms by the denominator
(x+5)-6*()=0
We add all the numbers together, and all the variables
(x+5)=0
We get rid of parentheses
x+5=0
We move all terms containing x to the left, all other terms to the right
x=-5

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