(x+5)/2+1/2=2x-(x-3)/8

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Solution for (x+5)/2+1/2=2x-(x-3)/8 equation: 



(x+5)/2+1/2=2x-(x-3)/8

We move all terms to the left:

(x+5)/2+1/2-(2x-(x-3)/8)=0

We calculate fractions


(x+5)/()+(-(2x-(x-3)*2)/()=0



We calculate terms in parentheses: +(-(2x-(x-3)*2)/(), so:

-(2x-(x-3)*2)/(

We multiply all the terms by the denominator


-(2x-(x-3)*2)



We calculate terms in parentheses: -(2x-(x-3)*2), so:

2x-(x-3)*2

We multiply parentheses

2x-2x+6

We add all the numbers together, and all the variables

6

Back to the equation:

-(6)



Back to the equation:

+(-6)



We add all the numbers together, and all the variables

(x+5)/()-6=0

We multiply all the terms by the denominator


(x+5)-6*()=0

We add all the numbers together, and all the variables

(x+5)=0

We get rid of parentheses

x+5=0

We move all terms containing x to the left, all other terms to the right

x=-5

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