(x+5)/2=4-(x+3)/7

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Solution for (x+5)/2=4-(x+3)/7 equation: 



(x+5)/2=4-(x+3)/7

We move all terms to the left:

(x+5)/2-(4-(x+3)/7)=0

We calculate fractions


x/()+(-(4-(x+3)*2)/()=0



We calculate terms in parentheses: +(-(4-(x+3)*2)/(), so:

-(4-(x+3)*2)/(

We multiply all the terms by the denominator


-(4-(x+3)*2)



We calculate terms in parentheses: -(4-(x+3)*2), so:

4-(x+3)*2

determiningTheFunctionDomain
-(x+3)*2+4

We multiply parentheses

-2x-6+4

We add all the numbers together, and all the variables

-2x-2

Back to the equation:

-(-2x-2)



We get rid of parentheses

2x+2

Back to the equation:

+(2x+2)



We get rid of parentheses

x/()+2x+2=0

We multiply all the terms by the denominator


x+2x*()+2*()=0

We add all the numbers together, and all the variables

x+2x*()=0

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