(x+5)/2=x-(2x-3)/3

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Solution for (x+5)/2=x-(2x-3)/3 equation: 



(x+5)/2=x-(2x-3)/3

We move all terms to the left:

(x+5)/2-(x-(2x-3)/3)=0

We calculate fractions


x/()+(-(x-(2x-3)*2)/()=0



We calculate terms in parentheses: +(-(x-(2x-3)*2)/(), so:

-(x-(2x-3)*2)/(

We multiply all the terms by the denominator


-(x-(2x-3)*2)



We calculate terms in parentheses: -(x-(2x-3)*2), so:

x-(2x-3)*2

We multiply parentheses

x-4x+6

We add all the numbers together, and all the variables

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

3x-6

Back to the equation:

+(3x-6)



We get rid of parentheses

x/()+3x-6=0

We multiply all the terms by the denominator


x+3x*()-6*()=0

We add all the numbers together, and all the variables

x+3x*()=0

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