(x+5)/3=(2-x)/4-2

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Solution for (x+5)/3=(2-x)/4-2 equation: 



(x+5)/3=(2-x)/4-2

We move all terms to the left:

(x+5)/3-((2-x)/4-2)=0

We add all the numbers together, and all the variables

(x+5)/3-((-1x+2)/4-2)=0

We calculate fractions


(4x+20)/()+(-((-1x+2)*3)/()=0



We calculate terms in parentheses: +(-((-1x+2)*3)/(), so:

-((-1x+2)*3)/(

We multiply all the terms by the denominator


-((-1x+2)*3)



We calculate terms in parentheses: -((-1x+2)*3), so:

(-1x+2)*3

We multiply parentheses

-3x+6

Back to the equation:

-(-3x+6)



We get rid of parentheses

3x-6

Back to the equation:

+(3x-6)



We get rid of parentheses

(4x+20)/()+3x-6=0

We multiply all the terms by the denominator


(4x+20)+3x*()-6*()=0

We add all the numbers together, and all the variables

(4x+20)+3x*()=0

We get rid of parentheses

4x+3x*()+20=0

We move all terms containing x to the left, all other terms to the right

4x+3x*()=-20

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