(x+5)/3=2-(x+6)/2

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Solution for (x+5)/3=2-(x+6)/2 equation: 



(x+5)/3=2-(x+6)/2

We move all terms to the left:

(x+5)/3-(2-(x+6)/2)=0

We calculate fractions


x/()+(-(2-(x+6)*3)/()=0



We calculate terms in parentheses: +(-(2-(x+6)*3)/(), so:

-(2-(x+6)*3)/(

We multiply all the terms by the denominator


-(2-(x+6)*3)



We calculate terms in parentheses: -(2-(x+6)*3), so:

2-(x+6)*3

determiningTheFunctionDomain
-(x+6)*3+2

We multiply parentheses

-3x-18+2

We add all the numbers together, and all the variables

-3x-16

Back to the equation:

-(-3x-16)



We get rid of parentheses

3x+16

Back to the equation:

+(3x+16)



We get rid of parentheses

x/()+3x+16=0

We multiply all the terms by the denominator


x+3x*()+16*()=0

We add all the numbers together, and all the variables

x+3x*()=0

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