(x+5)/5=2-(x+2)/2

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Solution for (x+5)/5=2-(x+2)/2 equation: 



(x+5)/5=2-(x+2)/2

We move all terms to the left:

(x+5)/5-(2-(x+2)/2)=0

We calculate fractions


x/()+(-(2-(x+2)*5)/()=0



We calculate terms in parentheses: +(-(2-(x+2)*5)/(), so:

-(2-(x+2)*5)/(

We multiply all the terms by the denominator


-(2-(x+2)*5)



We calculate terms in parentheses: -(2-(x+2)*5), so:

2-(x+2)*5

determiningTheFunctionDomain
-(x+2)*5+2

We multiply parentheses

-5x-10+2

We add all the numbers together, and all the variables

-5x-8

Back to the equation:

-(-5x-8)



We get rid of parentheses

5x+8

Back to the equation:

+(5x+8)



We get rid of parentheses

x/()+5x+8=0

We multiply all the terms by the denominator


x+5x*()+8*()=0

We add all the numbers together, and all the variables

x+5x*()=0

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