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(x+5)7x=525
We move all terms to the left:
(x+5)7x-(525)=0
We multiply parentheses
7x^2+35x-525=0
a = 7; b = 35; c = -525;
Δ = b2-4ac
Δ = 352-4·7·(-525)
Δ = 15925
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{15925}=\sqrt{1225*13}=\sqrt{1225}*\sqrt{13}=35\sqrt{13}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-35\sqrt{13}}{2*7}=\frac{-35-35\sqrt{13}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+35\sqrt{13}}{2*7}=\frac{-35+35\sqrt{13}}{14} $
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