(x+5)=(2+3x)/2

Solution for (x+5)=(2+3x)/2 equation:

(x+5)=(2+3x)/2

We move all terms to the left:

(x+5)-((2+3x)/2)=0

We add all the numbers together, and all the variables

(x+5)-((3x+2)/2)=0

We get rid of parentheses

x-((3x+2)/2)+5=0

We multiply all the terms by the denominator


x*2)-((3x+2)+5*2)=0

We add all the numbers together, and all the variables

x*2)-((3x+2)=0

Wy multiply elements

2x^2=0

a = 2; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·2·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{4}=0$