If it's not what You are looking for type in the equation solver your own equation and let us solve it.
(x+5)x=12.5.4
We move all terms to the left:
(x+5)x-(12.5.4)=0
We add all the numbers together, and all the variables
(x+5)x-5=0
We multiply parentheses
x^2+5x-5=0
a = 1; b = 5; c = -5;
Δ = b2-4ac
Δ = 52-4·1·(-5)
Δ = 45
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{45}=\sqrt{9*5}=\sqrt{9}*\sqrt{5}=3\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-3\sqrt{5}}{2*1}=\frac{-5-3\sqrt{5}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+3\sqrt{5}}{2*1}=\frac{-5+3\sqrt{5}}{2} $
| X/4-4=3x/4+-6 | | k-14=53 | | 8/9x-5/9x=6 | | 4x3+73=180 | | X/4+-4=3x/4+6 | | 24x-72=8(3x- | | 12=−2(−6x−3) | | 5(2x+3)-(19+x)=-40 | | 0.2=s+(-0.8) | | p(p+2)=15 | | 48-(3c+4)=2(c+5)+c | | ‐77=‐8(1–8x)+5(6x+5) | | X+2=1x=7 | | 6x+48=3x+44 | | -‐77=-‐8(1–8x)+5(6x+5) | | h-64=11 | | 12x-2(x+3)=34 | | 2/3+15(w-3)-2w/7=3/2-2w/3+9(2w-5) | | 10=k-1 | | 2-3y=4(2y+1) | | 3.8+0.03m=4.0+0.1m | | 1/7x+4/7x=10 | | 31=-7u+4(u+7) | | 1/2*(3x-8+7x+4)=33 | | 8x7=56=x2=112 | | A={x|xEN;x-15=22} | | 2/5x+1/10x=15 | | -10=-5r-15 | | x=3/8=-1/12 | | 9=-9+3c | | -3/x=3 | | x5=24/30 |