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(x+5/3)*(2*x-(2/5)) = 0
(x+5/3)*(2*x-2/5) = 0
( 2*x-2/5 )
2*x-2/5 = 0 // + 2/5
2*x = 2/5 // : 2
x = 2/5/2
x = 1/5
( x+5/3 )
x+5/3 = 0 // - 5/3
x = -5/3
x in { 1/5, -5/3 }
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