(x+5/x-7)-5=4x-40/13-x

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Solution for (x+5/x-7)-5=4x-40/13-x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+5/x-7-5 = 4*x-x-(40/13) // - 4*x-x-(40/13)

x-(4*x)+x+5/x+40/13-7-5 = 0

x-4*x+x+5/x+40/13-7-5 = 0

5*x^-1-2*x^1-116/13*x^0 = 0

(5*x^0-2*x^2-116/13*x^1)/(x^1) = 0 // * x^2

x^1*(5*x^0-2*x^2-116/13*x^1) = 0

x^1

(-116/13)*x-2*x^2+5 = 0

(-116/13)*x-2*x^2+5 = 0

DELTA = (-116/13)^2-(-2*4*5)

DELTA = 20216/169

DELTA > 0

x = ((20216/169)^(1/2)-(-116/13))/(-2*2) or x = (-(-116/13)-(20216/169)^(1/2))/(-2*2)

x = ((20216/169)^(1/2)+116/13)/(-4) or x = (116/13-(20216/169)^(1/2))/(-4)

x in { ((20216/169)^(1/2)+116/13)/(-4), (116/13-(20216/169)^(1/2))/(-4)} 

x in { ((20216/169)^(1/2)+116/13)/(-4), (116/13-(20216/169)^(1/2))/(-4) }

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