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(x+50)(x+30)=2*50*30
We move all terms to the left:
(x+50)(x+30)-(2*50*30)=0
We add all the numbers together, and all the variables
(x+50)(x+30)-3000=0
We multiply parentheses ..
(+x^2+30x+50x+1500)-3000=0
We get rid of parentheses
x^2+30x+50x+1500-3000=0
We add all the numbers together, and all the variables
x^2+80x-1500=0
a = 1; b = 80; c = -1500;
Δ = b2-4ac
Δ = 802-4·1·(-1500)
Δ = 12400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{12400}=\sqrt{400*31}=\sqrt{400}*\sqrt{31}=20\sqrt{31}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-20\sqrt{31}}{2*1}=\frac{-80-20\sqrt{31}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+20\sqrt{31}}{2*1}=\frac{-80+20\sqrt{31}}{2} $
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