(x+5i)(x-5i)=0

Solution for (x+5i)(x-5i)=0 equation:

Simplifying
(x + 5i)(x + -5i) = 0

Reorder the terms:
(5i + x)(x + -5i) = 0

Reorder the terms:
(5i + x)(-5i + x) = 0

Multiply (5i + x) * (-5i + x)
(5i * (-5i + x) + x(-5i + x)) = 0
((-5i * 5i + x * 5i) + x(-5i + x)) = 0

Reorder the terms:
((5ix + -25i2) + x(-5i + x)) = 0
((5ix + -25i2) + x(-5i + x)) = 0
(5ix + -25i2 + (-5i * x + x * x)) = 0
(5ix + -25i2 + (-5ix + x2)) = 0

Reorder the terms:
(5ix + -5ix + -25i2 + x2) = 0

Combine like terms: 5ix + -5ix = 0
(0 + -25i2 + x2) = 0
(-25i2 + x2) = 0

Solving
-25i2 + x2 = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1x2' to each side of the equation.
-25i2 + x2 + -1x2 = 0 + -1x2

Combine like terms: x2 + -1x2 = 0
-25i2 + 0 = 0 + -1x2
-25i2 = 0 + -1x2
Remove the zero:
-25i2 = -1x2

Divide each side by '-25'.
i2 = 0.04x2

Simplifying
i2 = 0.04x2

Take the square root of each side:
i = {-0.2x, 0.2x}