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(x+6)(2x-11)=0
We multiply parentheses ..
(+2x^2-11x+12x-66)=0
We get rid of parentheses
2x^2-11x+12x-66=0
We add all the numbers together, and all the variables
2x^2+x-66=0
a = 2; b = 1; c = -66;
Δ = b2-4ac
Δ = 12-4·2·(-66)
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-23}{2*2}=\frac{-24}{4} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+23}{2*2}=\frac{22}{4} =5+1/2 $
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