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(x+6)(4x+8)=x+8
We move all terms to the left:
(x+6)(4x+8)-(x+8)=0
We get rid of parentheses
(x+6)(4x+8)-x-8=0
We multiply parentheses ..
(+4x^2+8x+24x+48)-x-8=0
We add all the numbers together, and all the variables
(+4x^2+8x+24x+48)-1x-8=0
We get rid of parentheses
4x^2+8x+24x-1x+48-8=0
We add all the numbers together, and all the variables
4x^2+31x+40=0
a = 4; b = 31; c = +40;
Δ = b2-4ac
Δ = 312-4·4·40
Δ = 321
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(31)-\sqrt{321}}{2*4}=\frac{-31-\sqrt{321}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(31)+\sqrt{321}}{2*4}=\frac{-31+\sqrt{321}}{8} $
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