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(x+6)(6x-8)=0
We multiply parentheses ..
(+6x^2-8x+36x-48)=0
We get rid of parentheses
6x^2-8x+36x-48=0
We add all the numbers together, and all the variables
6x^2+28x-48=0
a = 6; b = 28; c = -48;
Δ = b2-4ac
Δ = 282-4·6·(-48)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1936}=44$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(28)-44}{2*6}=\frac{-72}{12} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(28)+44}{2*6}=\frac{16}{12} =1+1/3 $
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