(x+6)(x+8)-(x-7)(x-5)=0

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Solution for (x+6)(x+8)-(x-7)(x-5)=0 equation: 



(x+6)(x+8)-(x-7)(x-5)=0

We multiply parentheses ..

(+x^2+8x+6x+48)-(x-7)(x-5)=0

We get rid of parentheses

x^2+8x+6x-(x-7)(x-5)+48=0

We multiply parentheses ..

x^2-(+x^2-5x-7x+35)+8x+6x+48=0

We add all the numbers together, and all the variables

x^2-(+x^2-5x-7x+35)+14x+48=0

We get rid of parentheses

x^2-x^2+5x+7x+14x-35+48=0

We add all the numbers together, and all the variables

26x+13=0

We move all terms containing x to the left, all other terms to the right

26x=-13

x=-13/26

x=-1/2

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