(x+6)(x-1)-(x+3)(x-4)=5

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Solution for (x+6)(x-1)-(x+3)(x-4)=5 equation: 



(x+6)(x-1)-(x+3)(x-4)=5

We move all terms to the left:

(x+6)(x-1)-(x+3)(x-4)-(5)=0

We multiply parentheses ..

(+x^2-1x+6x-6)-(x+3)(x-4)-5=0

We get rid of parentheses

x^2-1x+6x-(x+3)(x-4)-6-5=0

We multiply parentheses ..

x^2-(+x^2-4x+3x-12)-1x+6x-6-5=0

We add all the numbers together, and all the variables

x^2-(+x^2-4x+3x-12)+5x-11=0

We get rid of parentheses

x^2-x^2+4x-3x+5x+12-11=0

We add all the numbers together, and all the variables

6x+1=0

We move all terms containing x to the left, all other terms to the right

6x=-1

x=-1/6

x=-1/6

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