(x+6)(x-3)=(x+7)(x+1)

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Solution for (x+6)(x-3)=(x+7)(x+1) equation: 



(x+6)(x-3)=(x+7)(x+1)

We move all terms to the left:

(x+6)(x-3)-((x+7)(x+1))=0

We multiply parentheses ..

(+x^2-3x+6x-18)-((x+7)(x+1))=0



We calculate terms in parentheses: -((x+7)(x+1)), so:

(x+7)(x+1)

We multiply parentheses ..

(+x^2+x+7x+7)

We get rid of parentheses

x^2+x+7x+7

We add all the numbers together, and all the variables

x^2+8x+7

Back to the equation:

-(x^2+8x+7)



We get rid of parentheses

x^2-x^2-3x+6x-8x-18-7=0

We add all the numbers together, and all the variables

-5x-25=0

We move all terms containing x to the left, all other terms to the right

-5x=25

x=25/-5

x=-5

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