(x+6)(x-7)-(x+3)(x-8)=0

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Solution for (x+6)(x-7)-(x+3)(x-8)=0 equation: 



(x+6)(x-7)-(x+3)(x-8)=0

We multiply parentheses ..

(+x^2-7x+6x-42)-(x+3)(x-8)=0

We get rid of parentheses

x^2-7x+6x-(x+3)(x-8)-42=0

We multiply parentheses ..

x^2-(+x^2-8x+3x-24)-7x+6x-42=0

We add all the numbers together, and all the variables

x^2-(+x^2-8x+3x-24)-1x-42=0

We get rid of parentheses

x^2-x^2+8x-3x-1x+24-42=0

We add all the numbers together, and all the variables

4x-18=0

We move all terms containing x to the left, all other terms to the right

4x=18

x=18/4

x=4+1/2

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