(x+6)/(x+3)=((3)/(x+3))+4

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Solution for (x+6)/(x+3)=((3)/(x+3))+4 equation: 


D( x )

x+3 = 0

x+3 = 0

x+3 = 0

x+3 = 0 // - 3

x = -3

x in (-oo:-3) U (-3:+oo)

(x+6)/(x+3) = 3/(x+3)+4 // - 3/(x+3)+4

(x+6)/(x+3)-(3/(x+3))-4 = 0

(x+6)/(x+3)-3*(x+3)^-1-4 = 0

(x+6)/(x+3)-3/(x+3)-4 = 0

(x+6)/(x+3)-3/(x+3)+(-4*(x+3))/(x+3) = 0

x-4*(x+3)-3+6 = 0

x-4*x-12+3 = 0

-3*x-9 = 0

(-3*x-9)/(x+3) = 0

(-3*x-9)/(x+3) = 0 // * x+3

-3*x-9 = 0

-3*x-9 = 0 // + 9

-3*x = 9 // : -3

x = 9/(-3)

x = -3

x in { -3} 

x belongs to the empty set

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