(x+69(3x+12)=3(3x2)

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Solution for (x+69(3x+12)=3(3x2) equation: 



(x+69(3x+12)=3(3x^2)

We move all terms to the left:

(x+69(3x+12)-(3(3x^2))=0

determiningTheFunctionDomain
(x+69(3x+12)-33x^2=0

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