(x+7)(x+7)-12x=(x-5)(x-5)

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Solution for (x+7)(x+7)-12x=(x-5)(x-5) equation: 



(x+7)(x+7)-12x=(x-5)(x-5)

We move all terms to the left:

(x+7)(x+7)-12x-((x-5)(x-5))=0

We add all the numbers together, and all the variables

-12x+(x+7)(x+7)-((x-5)(x-5))=0

We multiply parentheses ..

(+x^2+7x+7x+49)-12x-((x-5)(x-5))=0



We calculate terms in parentheses: -((x-5)(x-5)), so:

(x-5)(x-5)

We multiply parentheses ..

(+x^2-5x-5x+25)

We get rid of parentheses

x^2-5x-5x+25

We add all the numbers together, and all the variables

x^2-10x+25

Back to the equation:

-(x^2-10x+25)



We get rid of parentheses

x^2-x^2+7x+7x-12x+10x+49-25=0

We add all the numbers together, and all the variables

12x+24=0

We move all terms containing x to the left, all other terms to the right

12x=-24

x=-24/12

x=-2

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