(x+7)(x-1)=(x+1)(x-3)

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Solution for (x+7)(x-1)=(x+1)(x-3) equation: 



(x+7)(x-1)=(x+1)(x-3)

We move all terms to the left:

(x+7)(x-1)-((x+1)(x-3))=0

We multiply parentheses ..

(+x^2-1x+7x-7)-((x+1)(x-3))=0



We calculate terms in parentheses: -((x+1)(x-3)), so:

(x+1)(x-3)

We multiply parentheses ..

(+x^2-3x+x-3)

We get rid of parentheses

x^2-3x+x-3

We add all the numbers together, and all the variables

x^2-2x-3

Back to the equation:

-(x^2-2x-3)



We get rid of parentheses

x^2-x^2-1x+7x+2x-7+3=0

We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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