(x+7)(x-1)=128

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Solution for (x+7)(x-1)=128 equation:



(x+7)(x-1)=128
We move all terms to the left:
(x+7)(x-1)-(128)=0
We multiply parentheses ..
(+x^2-1x+7x-7)-128=0
We get rid of parentheses
x^2-1x+7x-7-128=0
We add all the numbers together, and all the variables
x^2+6x-135=0
a = 1; b = 6; c = -135;
Δ = b2-4ac
Δ = 62-4·1·(-135)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{576}=24$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(6)-24}{2*1}=\frac{-30}{2} =-15 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(6)+24}{2*1}=\frac{18}{2} =9 $

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