(x+7)(x-2)+(x+2)(x-4)=(5+x)-53

Solution for (x+7)(x-2)+(x+2)(x-4)=(5+x)-53 equation:

(x+7)(x-2)+(x+2)(x-4)=(5+x)-53

We move all terms to the left:

(x+7)(x-2)+(x+2)(x-4)-((5+x)-53)=0

We add all the numbers together, and all the variables

(x+7)(x-2)+(x+2)(x-4)-((x+5)-53)=0

We multiply parentheses ..

(+x^2-2x+7x-14)+(x+2)(x-4)-((x+5)-53)=0


We calculate terms in parentheses: -((x+5)-53), so:

(x+5)-53

We get rid of parentheses

x+5-53

We add all the numbers together, and all the variables

x-48

Back to the equation:

-(x-48)


We get rid of parentheses

x^2-2x+7x+(x+2)(x-4)-x-14+48=0

We multiply parentheses ..

x^2+(+x^2-4x+2x-8)-2x+7x-x-14+48=0

We add all the numbers together, and all the variables

x^2+(+x^2-4x+2x-8)+4x+34=0

We get rid of parentheses

x^2+x^2-4x+2x+4x-8+34=0

We add all the numbers together, and all the variables

2x^2+2x+26=0

a = 2; b = 2; c = +26;
Δ = b2-4ac
Δ = 22-4·2·26
Δ = -204
Delta is less than zero, so there is no solution for the equation