(x+7)/4x+1=(x+5)/x

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Solution for (x+7)/4x+1=(x+5)/x equation: 



(x+7)/4x+1=(x+5)/x

We move all terms to the left:

(x+7)/4x+1-((x+5)/x)=0



Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R





Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(x+7)*x)/4x^2+(-((x+5)*4x)/4x^2+1=0

We calculate fractions


((x+7)*x)*4x^2)/(4x^2+(*4x^2)+(-((x+5)*4x)*4x^2)/(4x^2+(*4x^2)+1=0

We get rid of parentheses

((x+7)*x)*4x^2)/(4x^2+*4x^2+(-((x+5)*4x)*4x^2)/(4x^2+(*4x^2)+1=0

We calculate fractions


*4x^2+(((x+7)*x)*4x^2)*(4x^2+*4x^2+1)/((4x^2*(4x^2+(*4x^2)+1)+((-((x+5)*4x)*4x^2)*4x^2/((4x^2*(4x^2+(*4x^2)+1)=0



We calculate terms in parentheses: +(((x+7)*x)*4x^2)*(4x^2+*4x^2+1)/((4x^2*(4x^2+(*4x^2)+1)+((-((x+5)*4x)*4x^2)*4x^2/((4x^2*(4x^2+(*4x^2)+1), so:

((x+7)*x)*4x^2)*(4x^2+*4x^2+1)/((4x^2*(4x^2+(*4x^2)+1)+((-((x+5)*4x)*4x^2)*4x^2/((4x^2*(4x^2+(*4x^2)+1

We can not solve this equation

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