(x+7/5x)+1=(x-5/x)

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Solution for (x+7/5x)+1=(x-5/x) equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

x+(7/5)*x+1 = x-(5/x) // - x-(5/x)

x+(7/5)*x-x+5/x+1 = 0

7/5*x^1+5*x^-1+1*x^0 = 0

(7/5*x^2+1*x^1+5*x^0)/(x^1) = 0 // * x^2

x^1*(7/5*x^2+1*x^1+5*x^0) = 0

x^1

(7/5)*x^2+x+5 = 0

(7/5)*x^2+x+5 = 0

DELTA = 1^2-(4*5*(7/5))

DELTA = -27

DELTA < 0

x in { } 

x belongs to the empty set

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