(x+7/x)*(6/(3x+21))

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Solution for (x+7/x)*(6/(3x+21)) equation: 


D( x )

x = 0

3*x+21 = 0

x = 0

x = 0

3*x+21 = 0

3*x+21 = 0

3*x+21 = 0 // - 21

3*x = -21 // : 3

x = -21/3

x = -7

x in (-oo:-7) U (-7:0) U (0:+oo)

(x+7/x)*(6/(3*x+21)) = 0

(6*(x+7*x^-1))/(3*x+21) = 0

x+7*x^-1 = 0

x^-1*(x^2+7) = 0

1*x^2 = -7 // : 1

x^2 = -7

1/x = 0

(6*x^-1)/(3*x+21) = 0

1*x^-1 = 0 // : 1

x^-1 = 0

x naleu017Cy do O

x belongs to the empty set

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