(x+8)(2x-11)=0

Solution for (x+8)(2x-11)=0 equation:

(x+8)(2x-11)=0

We multiply parentheses ..

(+2x^2-11x+16x-88)=0

We get rid of parentheses

2x^2-11x+16x-88=0

We add all the numbers together, and all the variables

2x^2+5x-88=0

a = 2; b = 5; c = -88;
Δ = b2-4ac
Δ = 52-4·2·(-88)
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{729}=27$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-27}{2*2}=\frac{-32}{4}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+27}{2*2}=\frac{22}{4}
=5+1/2
$