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(x+8)(2x-6)=39(20)
We move all terms to the left:
(x+8)(2x-6)-(39(20))=0
determiningTheFunctionDomain (x+8)(2x-6)-3920=0
We multiply parentheses ..
(+2x^2-6x+16x-48)-3920=0
We get rid of parentheses
2x^2-6x+16x-48-3920=0
We add all the numbers together, and all the variables
2x^2+10x-3968=0
a = 2; b = 10; c = -3968;
Δ = b2-4ac
Δ = 102-4·2·(-3968)
Δ = 31844
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{31844}=\sqrt{4*7961}=\sqrt{4}*\sqrt{7961}=2\sqrt{7961}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{7961}}{2*2}=\frac{-10-2\sqrt{7961}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{7961}}{2*2}=\frac{-10+2\sqrt{7961}}{4} $
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