(x+8)(4x-10)=

Solution for (x+8)(4x-10)= equation:

(x+8)(4x-10)=

We move all terms to the left:

(x+8)(4x-10)-()=0

We add all the numbers together, and all the variables

(x+8)(4x-10)=0

We multiply parentheses ..

(+4x^2-10x+32x-80)=0

We get rid of parentheses

4x^2-10x+32x-80=0

We add all the numbers together, and all the variables

4x^2+22x-80=0

a = 4; b = 22; c = -80;
Δ = b2-4ac
Δ = 222-4·4·(-80)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22)-42}{2*4}=\frac{-64}{8}
=-8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22)+42}{2*4}=\frac{20}{8}
=2+1/2
$