(x+8)(x)(x+4)(x+12)=(x+8)(x)+160

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Solution for (x+8)(x)(x+4)(x+12)=(x+8)(x)+160 equation: 



(x+8)(x)(x+4)(x+12)=(x+8)(x)+160

We move all terms to the left:

(x+8)(x)(x+4)(x+12)-((x+8)(x)+160)=0

We multiply parentheses ..

(x+8)x(+x^2+12x+4x+48)-((x+8)x+160)=0



We calculate terms in parentheses: -((x+8)x+160), so:

(x+8)x+160

We multiply parentheses

x^2+8x+160

Back to the equation:

-(x^2+8x+160)



We get rid of parentheses

(x+8)x(+x^2+12x+4x+48)-x^2-8x-160=0

We add all the numbers together, and all the variables

-1x^2+(x+8)x(+x^2+12x+4x+48)-8x-160=0

We move all terms containing x to the left, all other terms to the right

-1x^2+(x+8)x(+x^2+12x+4x+48)-8x=160

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