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(x+8)(x+4)=77
We move all terms to the left:
(x+8)(x+4)-(77)=0
We multiply parentheses ..
(+x^2+4x+8x+32)-77=0
We get rid of parentheses
x^2+4x+8x+32-77=0
We add all the numbers together, and all the variables
x^2+12x-45=0
a = 1; b = 12; c = -45;
Δ = b2-4ac
Δ = 122-4·1·(-45)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-18}{2*1}=\frac{-30}{2} =-15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+18}{2*1}=\frac{6}{2} =3 $
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