(x+8)(x-1)=(x+2)*2

Solution for (x+8)(x-1)=(x+2)*2 equation:

(x+8)(x-1)=(x+2)*2

We move all terms to the left:

(x+8)(x-1)-((x+2)*2)=0

We multiply parentheses ..

(+x^2-1x+8x-8)-((x+2)*2)=0


We calculate terms in parentheses: -((x+2)*2), so:

(x+2)*2

We multiply parentheses

2x+4

Back to the equation:

-(2x+4)


We get rid of parentheses

x^2-1x+8x-2x-8-4=0

We add all the numbers together, and all the variables

x^2+5x-12=0

a = 1; b = 5; c = -12;
Δ = b2-4ac
Δ = 52-4·1·(-12)
Δ = 73
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-\sqrt{73}}{2*1}=\frac{-5-\sqrt{73}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+\sqrt{73}}{2*1}=\frac{-5+\sqrt{73}}{2}
$