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(x+8)(x-5)=(x+5)(x-3)
We move all terms to the left:
(x+8)(x-5)-((x+5)(x-3))=0
We multiply parentheses ..
(+x^2-5x+8x-40)-((x+5)(x-3))=0
We calculate terms in parentheses: -((x+5)(x-3)), so:We get rid of parentheses
(x+5)(x-3)
We multiply parentheses ..
(+x^2-3x+5x-15)
We get rid of parentheses
x^2-3x+5x-15
We add all the numbers together, and all the variables
x^2+2x-15
Back to the equation:
-(x^2+2x-15)
x^2-x^2-5x+8x-2x-40+15=0
We add all the numbers together, and all the variables
x-25=0
We move all terms containing x to the left, all other terms to the right
x=25
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